Skip to content
Study Notes/Civil Engineering/Structural Engineering

Structural Engineering

Strength of materials, concrete design, steel structures, and structural analysis

1. Stress & Strain

Types of Stress

Normal Stress (σ)

σ = P/A

Perpendicular to cross-section

  • Tensile (+): Pulls apart
  • Compressive (-): Pushes together

Shear Stress (τ)

τ = V/A

Parallel to cross-section

  • Single shear: τ = P/A
  • Double shear: τ = P/2A

Strain & Deformation

PropertyFormulaDescription
Normal Strainε = ΔL/LChange in length per unit length
Shear Strainγ = τ/GAngular distortion (radians)
Young's ModulusE = σ/εSlope of stress-strain (elastic region)
Shear ModulusG = τ/γG = E/[2(1+ν)]
Poisson's Ratioν = -ε_lat/ε_axialTypically 0.25-0.35 for metals

Axial Deformation

δ = PL/AE

For non-uniform members: δ = Σ(PᵢLᵢ/AᵢEᵢ)

Thermal Stress

Free Expansion

δ_T = αLΔT

No stress if free to expand

Constrained Member

σ_T = EαΔT

α = coefficient of thermal expansion

2. Beam Analysis

Bending Stress

σ = Mc/I = M/S

M = bending moment, c = distance from neutral axis, I = moment of inertia, S = section modulus

Shear Stress in Beams

τ = VQ/Ib

  • V = shear force
  • Q = first moment of area above/below point
  • I = moment of inertia of entire section
  • b = width at point of interest

Common Beam Formulas

Beam TypeMax MomentMax Deflection
SS - Center Point LoadPL/4PL³/48EI
SS - Uniform LoadwL²/85wL⁴/384EI
Cantilever - End LoadPLPL³/3EI
Cantilever - Uniform LoadwL²/2wL⁴/8EI
Fixed Both Ends - Center LoadPL/8PL³/192EI
Fixed Both Ends - Uniform LoadwL²/12wL⁴/384EI

Moment of Inertia (I)

Rectangle

I = bh³/12

About centroidal axis parallel to b

Circle

I = πd⁴/64 = πr⁴/4

Triangle

I = bh³/36

About centroidal axis

Parallel Axis Theorem

I = I_c + Ad²

3. Columns & Compression Members

Euler's Buckling Formula

P_cr = π²EI/(KL)²

Critical (buckling) load for long slender columns

Effective Length Factor (K)

K = 1.0

Pinned-Pinned

K = 0.5

Fixed-Fixed

K = 0.7

Fixed-Pinned

K = 2.0

Fixed-Free

Slenderness Ratio

λ = KL/r

  • r = radius of gyration = √(I/A)
  • Long column: Euler formula applies
  • Short column: Direct compression (P/A)
  • Intermediate: Use empirical formulas

4. Reinforced Concrete Design

USD (Ultimate Strength Design)

φMₙ ≥ Mᵤ

Design strength must exceed factored load

Flexural Design Formulas

ParameterFormula
Nominal MomentMₙ = Asfy(d - a/2)
Compression Block Deptha = Asfy/(0.85f'c·b)
Neutral Axis Depthc = a/β₁
Steel Ratioρ = As/bd
Minimum Steel Ratioρ_min = 1.4/fy or √f'c/(4fy)
Maximum Steel Ratioρ_max = 0.75ρ_b

Beta Factor (β₁)

  • f'c ≤ 28 MPa: β₁ = 0.85
  • 28 < f'c ≤ 56 MPa: β₁ = 0.85 - 0.05(f'c - 28)/7
  • f'c > 56 MPa: β₁ = 0.65

Shear Design

Concrete Shear Strength

Vc = 0.17√f'c·bw·d

Simplified formula (NSCP)

Stirrup Contribution

Vs = Av·fy·d/s

For vertical stirrups

5. Steel Design

LRFD vs ASD

LRFD (Load & Resistance Factor)

φRₙ ≥ ΣγᵢQᵢ

Factor loads up, resistance down

ASD (Allowable Stress)

Rₙ/Ω ≥ ΣQᵢ

Compare to allowable stress

Tension Members

  • Gross Section Yielding: Pₙ = Fy·Ag
  • Net Section Fracture: Pₙ = Fu·Ae
  • Effective Net Area: Ae = U·An
  • U (Shear Lag Factor): Depends on connection

Compression Members

Critical Stress (Fcr)

  • KL/r ≤ 4.71√(E/Fy): Inelastic buckling
  • KL/r > 4.71√(E/Fy): Elastic buckling (Euler)

6. Structural Analysis Methods

Truss Analysis

Method of Joints

  • Isolate each joint
  • Apply equilibrium: ΣFx = 0, ΣFy = 0
  • Maximum 2 unknowns per joint
  • Start at joint with ≤ 2 unknowns

Method of Sections

  • Cut through truss (max 3 members)
  • Apply equilibrium to section
  • ΣFx = 0, ΣFy = 0, ΣM = 0
  • Choose moment point to eliminate unknowns

Indeterminate Structures

MethodApplication
Moment DistributionContinuous beams and frames; iterative
Slope-DeflectionRelates moments to rotations; simultaneous equations
Three-Moment EquationContinuous beams; relates moments at three supports
Conjugate BeamDeflection and slope calculation

Moment Distribution Concepts

  • Distribution Factor (DF): K/(ΣK) where K = I/L (stiffness)
  • Carry-Over Factor: 0.5 for prismatic members (far end fixed)
  • Fixed End Moments: Standard formulas for various loadings

7. Load Combinations (NSCP)

Strength Design Combinations

  • U = 1.4D
  • U = 1.2D + 1.6L + 0.5(Lr or S or R)
  • U = 1.2D + 1.6(Lr or S or R) + (L or 0.5W)
  • U = 1.2D + 1.0W + L + 0.5(Lr or S or R)
  • U = 1.2D + 1.0E + L + 0.2S
  • U = 0.9D + 1.0W
  • U = 0.9D + 1.0E

Load Notation

  • D: Dead load
  • L: Live load
  • Lr: Roof live load
  • S: Snow load
  • R: Rain load
  • W: Wind load
  • E: Earthquake load
  • F: Fluid load

Strength Reduction Factors (φ)

  • Flexure (tension-controlled): φ = 0.90
  • Shear and torsion: φ = 0.75
  • Compression (tied columns): φ = 0.65
  • Compression (spiral columns): φ = 0.75
  • Bearing: φ = 0.65

8. Connections

Bolted Connections

Bolt Shear Strength

Rₙ = Fₙᵥ × Aᵦ × n

n = number of shear planes

Bearing Strength

Rₙ = 2.4dtFᵤ

Standard holes

Welded Connections

Fillet Weld Strength

Rₙ = 0.6FEXX × (0.707 × a) × L

  • FEXX = electrode strength (e.g., E70 = 482 MPa)
  • a = weld leg size
  • L = effective length

Key Takeaways for the Board Exam

  • Bending stress: σ = Mc/I = M/S
  • Euler buckling: Pcr = π²EI/(KL)²
  • RC nominal moment: Mₙ = Asfy(d - a/2)
  • Compression block: a = Asfy/(0.85f'c·b)
  • K factors: P-P=1.0, F-F=0.5, F-P=0.7, F-Free=2.0
  • SS uniform load: M_max = wL²/8
  • β₁ = 0.85 for f'c ≤ 28 MPa
  • Shear design: φVₙ ≥ Vᵤ; Vₙ = Vc + Vs